Question

Compressibility of water is $5\times {10}^{-10}m/N.$ The change in volume of 100 mL water subjected to $15\times {10}^6$ Pa pressure will

• A. no change
• B. increase by 0.98 mL
• C. decrease by 0.75 mL
• D. increase by 1.50 mL

Answer 1

Answer: (C)

Compressibility $K=\frac{1}{B}=\frac{\Delta V}{V\Delta p}$ $\therefore$ $5\times {10}^{-10}=\frac{\Delta V}{100\times {10}^{-3}\times 15\times {10}^6}$ $\Rightarrow$ $\Delta V=5\times {10}^{-10}\times 100\times {10}^{-3}\times 15\times {10}^6$ $=0.75mL$ Since, pressure increases, so volume will decrease.