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  4. Compressibility of water is 5× 10-10m/N. The change in volume of 100 mL water subjected to 15× 106 Pa pressure will

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Q. Compressibility of water is $ 5\times {{10}^{-10}}m/N. $ The change in volume of 100 mL water subjected to $ 15\times {{10}^{6}} $ Pa pressure will

MGIMS WardhaMGIMS Wardha 2011

Solution:

Compressibility $ K=\frac{1}{B}=\frac{\Delta V}{V\Delta p} $ $ \therefore $ $ 5\times {{10}^{-10}}=\frac{\Delta V}{100\times {{10}^{-3}}\times 15\times {{10}^{6}}} $ $ \Rightarrow $ $ \Delta V=5\times {{10}^{-10}}\times 100\times {{10}^{-3}}\times 15\times {{10}^{6}} $ $ =0.75mL $ Since, pressure increases, so volume will decrease.