Compound having formula C8H10 forms two isomers P and Q. On oxidation P gives benzoic acid and Q gives phthalic acid. The isomers P and Q are

Question

Compound having formula C8H10 forms two isomers P and Q. On oxidation P gives benzoic acid and Q gives phthalic acid. The isomers P and Q are (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Alk. KM nO4 oxidises the entire side chain of alkyl benzene to -COOH group irrespective of the length of the carbon chain. If there are two or more alkyl groups, each alkyl chain is oxidised to a -COOH group.

Q. Compound having formula $C_{8} H_{10}$ forms two isomers $P$ and $Q$ . On oxidation $P$ gives benzoic acid and $Q$ gives phthalic acid. The isomers $P$ and $Q$ are

Alk. $K M n O_{4}$ oxidises the entire side chain of alkyl benzene to $- COO H$ group irrespective of the length of the carbon chain. If there are two or more alkyl groups, each alkyl chain is oxidised to a $- COO H$ group.

Q. Compound having formula C8​H10​ forms two isomers P and Q. On oxidation P gives benzoic acid and Q gives phthalic acid. The isomers P and Q are

Alk. KMnO4​ oxidises the entire side chain of alkyl benzene to −COOH group irrespective of the length of the carbon chain. If there are two or more alkyl groups, each alkyl chain is oxidised to a −COOH group.

Q. Compound having formula $C_{8} H_{10}$ forms two isomers $P$ and $Q$ . On oxidation $P$ gives benzoic acid and $Q$ gives phthalic acid. The isomers $P$ and $Q$ are

Alk. $K M n O_{4}$ oxidises the entire side chain of alkyl benzene to $- COO H$ group irrespective of the length of the carbon chain. If there are two or more alkyl groups, each alkyl chain is oxidised to a $- COO H$ group.