Compound (A) (molecular formula C3H8O ) is treated with acidified potassium dichromate td form a product B (molecular formula C3H6O). 'B' forms a shining silver mirror on warming with ammoniacal silver nitrate. 'B' when treated with an aqueous solution of H2NCONHNH2, HCl and sodium acetate gives a product 'C'. Identify the structure of 'C',

Question

Compound (A) (molecular formula C3H8O ) is treated with acidified potassium dichromate td form a product B (molecular formula C3H6O). 'B' forms a shining silver mirror on warming with ammoniacal silver nitrate. 'B' when treated with an aqueous solution of H2NCONHNH2, HCl and sodium acetate gives a product 'C'. Identify the structure of 'C', (A) CH3CH2CH = NNHCONH2 (B) (CH3)2C = NNHCONH2 (C) (CH3)2C = NCONHNH2 (D) CH3CH2CH = NCONHNH2

Tardigrade Admin · Accepted Answer

Correct answer is (a) CH3CH2CH = NNHCONH2

$C H_{3} C H_{2} C H = NN H CON H_{2}$

$(C H_{3})_{2} C = NN H CON H_{2}$

$(C H_{3})_{2} C = NCON H N H_{2}$

$C H_{3} C H_{2} C H = NCON H N H_{2}$

Correct answer is (a) $C H_{3} C H_{2} C H = NN H CON H_{2}$

CH3​CH2​CH=NNHCONH2​

(CH3​)2​C=NNHCONH2​

(CH3​)2​C=NCONHNH2​

CH3​CH2​CH=NCONHNH2​

Correct answer is (a) CH3​CH2​CH=NNHCONH2​

$C H_{3} C H_{2} C H = NN H CON H_{2}$

$(C H_{3})_{2} C = NN H CON H_{2}$

$(C H_{3})_{2} C = NCON H N H_{2}$

$C H_{3} C H_{2} C H = NCON H N H_{2}$

Correct answer is (a) $C H_{3} C H_{2} C H = NN H CON H_{2}$