Compound A contains 8.7 % Hydrogen, 74 % Carbon and 17.3 % Nitrogen. The molecular formula of the compound is, Given: Atomic masses of C , H and N are 12,1 and 14 amu respectively. The molar mass of the compound A is 162 g mol -1.

Question

Compound A contains 8.7 % Hydrogen, 74 % Carbon and 17.3 % Nitrogen. The molecular formula of the compound is, Given: Atomic masses of C , H and N are 12,1 and 14 amu respectively. The molar mass of the compound A is 162 g mol -1. (A) C 4 H 6 N 2 (B) C 2 H 3 N (C) C 5 H 7 N (D) C 10 H 14 N 2

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/a8012115b5667e7d4211b5f2cc9962b2-.png" /> Emperical formula = C 5 NH 7 Emperical weight =81 Multiplying factor =(162/81)=2 Molecular formula = C 10 N 2 H 14

Q. Compound $A$ contains $8.7%$ Hydrogen, $74%$ Carbon and $17.3%$ Nitrogen. The molecular formula of the compound is,
Given : Atomic masses of $C, H$ and $N$ are $12, 1$ and $14$ amu respectively.
The molar mass of the compound $A$ is $162 g m o l^{- 1}$ .

$C_{4} H_{6} N_{2}$

$C_{2} H_{3} N$

$C_{5} H_{7} N$

$C_{10} H_{14} N_{2}$

Emperical formula $= C_{5} N H_{7}$
Emperical weight $= 81$
Multiplying factor $= \frac{162}{81} = 2$
Molecular formula $= C_{10} N_{2} H_{14}$

Q. Compound A contains 8.7% Hydrogen, 74% Carbon and 17.3% Nitrogen. The molecular formula of the compound is, Given : Atomic masses of C,H and N are 12,1 and 14 amu respectively. The molar mass of the compound A is 162gmol−1.

C4​H6​N2​

C2​H3​N

C5​H7​N

C10​H14​N2​