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Q. Compound $A$ contains $8.7\%$ Hydrogen, $74\%$ Carbon and $17.3\%$ Nitrogen. The molecular formula of the compound is,
Given : Atomic masses of $C , H$ and $N$ are $12,1$ and $14$ amu respectively.
The molar mass of the compound $A$ is $162 \,g \,mol ^{-1}$.

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Solution:

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Emperical formula $= C _{5} NH _{7}$
Emperical weight $=81$
Multiplying factor $=\frac{162}{81}=2$
Molecular formula $= C _{10} N _{2} H _{14}$