Compound A , C 5 H 10 O 5, given a tetraacetate with AC 2 O and oxidation of A with Br 2- H 2 O gives an acid, C 5 H 10 O 6. Reduction of A with HI gives isopentane. The possible structure of A is:

Question

Compound A , C 5 H 10 O 5, given a tetraacetate with AC 2 O and oxidation of A with Br 2- H 2 O gives an acid, C 5 H 10 O 6. Reduction of A with HI gives isopentane. The possible structure of A is: (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

(i) Formation of tetraacetete with Ac 2 O means compound A has four - OH linkage. Reduction of A with HI gives Isopentane i.e. molecule contains five carbon atom.

Q. Compound $A, C_{5} H_{10} O_{5}$ , given a tetraacetate with $A C_{2} O$ and oxidation of $A$ with $B r_{2} - H_{2} O$ gives an acid, $C_{5} H_{10} O_{6}$ . Reduction of $A$ with $H I$ gives isopentane. The possible structure of $A$ is:

(i) Formation of tetraacetete with $A c_{2} O$ means compound $A$ has four $- O H$ linkage.
Reduction of A with $H I$ gives Isopentane i.e. molecule contains five carbon atom.

Q. Compound A,C5​H10​O5​, given a tetraacetate with AC2​O and oxidation of A with Br2​−H2​O gives an acid, C5​H10​O6​. Reduction of A with HI gives isopentane. The possible structure of A is:

(i) Formation of tetraacetete with Ac2​O means compound A has four −OH linkage. Reduction of A with HI gives Isopentane i.e. molecule contains five carbon atom.

Q. Compound $A, C_{5} H_{10} O_{5}$ , given a tetraacetate with $A C_{2} O$ and oxidation of $A$ with $B r_{2} - H_{2} O$ gives an acid, $C_{5} H_{10} O_{6}$ . Reduction of $A$ with $H I$ gives isopentane. The possible structure of $A$ is:

(i) Formation of tetraacetete with $A c_{2} O$ means compound $A$ has four $- O H$ linkage.
Reduction of A with $H I$ gives Isopentane i.e. molecule contains five carbon atom.