Question

Column I		Column II
A		p
B		q
C		r
D		s

• A. A -(r), B -(t), C - (q), D - (s),
• B. A -(r), B -(s), C - (p), D - (q)
• C. A -(p), B -(q), C - (r), D - (t)
• D. A -(r), B -(p), C - (s), D - (q)

Answer 1

Answer: (D)

$(a\to r)$ Bulky base, Hofmann elimination, less substituted alkene as in (R) is obtained
$(b\to p)$ Simple base, Saytzeff elimination, more substituted alkene as in (p) is obtained
$(c\to s)$ Same explanation as in (a)
$(d\to q)$ Same explanation as in (b)