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Question
Mathematics
Coefficient of x13 in the expansion of (1-x)5(1+x+x2+x3)4 is
Q. Coefficient of
x
13
in the expansion of
(
1
−
x
)
5
(
1
+
x
+
x
2
+
x
3
)
4
is
1471
199
Binomial Theorem
Report Error
A
4
B
6
C
32
D
5
Solution:
Expression
=
(
1
−
x
)
5
⋅
(
1
+
x
)
4
(
1
+
x
2
)
4
=
(
1
−
x
)
(
1
−
x
2
)
4
(
1
+
x
2
)
4
=
(
1
−
x
)
(
1
−
x
4
)
4
∴
Coefficient of
x
13
=
−
4
C
3
(
−
1
)
3
=
4