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Mathematics
Coefficient of x11 in the expansion of (1 + x2)4 (1 + x3)7 (1 + x4)12
Q. Coefficient of
x
11
in the expansion of
(
1
+
x
2
)
4
(
1
+
x
3
)
7
(
1
+
x
4
)
12
4763
222
JEE Advanced
JEE Advanced 2014
Binomial Theorem
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A
1051
16%
B
1106
33%
C
1113
37%
D
1120
14%
Solution:
2
x
1
+
3
x
2
+
4
x
3
=
11
Possibilities are
(
0
,
1
,
2
)
;
(
1
,
3
,
0
)
;
(
2
,
1
,
1
)
;
(
4
,
1
,
0
)
.
∴
Required coefficients
=
(
4
C
0
×
7
C
1
×
12
C
2
)
+
(
4
C
1
×
7
C
3
×
12
C
0
)
+
(
4
C
2
×
7
C
1
×
12
C
1
)
+
(
4
C
4
×
7
C
1
×
1
)
=
(
1
×
7
×
66
)
+
(
4
×
35
×
1
)
+
(
6
×
7
×
12
)
+
(
1
×
7
)
=
462
+
140
+
504
+
7
=
1113