CNG is an important transportation fuel. When 100 g CNG is mixed with 208 oxygen in vehicles, it leads to the formation of CO 2 and H 2 O and produces large quantity of heat during this combustion, then the amount of carbon dioxide, produced in grams is . [nearest integer] [Assume CNG to be methane]

Question

CNG is an important transportation fuel. When 100 g CNG is mixed with 208 oxygen in vehicles, it leads to the formation of CO 2 and H 2 O and produces large quantity of heat during this combustion, then the amount of carbon dioxide, produced in grams is . [nearest integer] [Assume CNG to be methane] (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/f7bac9c559e07e0d6a9d5c3ea831967c-.png" /> ( text Mole / text Stoi. Coeff. ) stackrel (6.25/1) (6.5/2)=3.25 So, O 2 is limiting reagent Mole - Mole analysis ( n O 2/2)=( n co 2/1) (6.5/2)= n co 2 Mass of CO 2=(6.5/2) × 44=143 gm

Stoi. Coeff. Mole ​16.25​​26.5​=3.25 So, O2​ is limiting reagent Mole - Mole analysis 2nO2​​​=1nco2​​​ 26.5​=nco2​​ Mass of CO2​=26.5​×44=143gm

$\frac{Mole}{Stoi. Coeff.} \frac{6.25}{1} \frac{6.5}{2} = 3.25$
So, $O_{2}$ is limiting reagent
Mole - Mole analysis
$\frac{n _{O_{2}}}{2} = \frac{n _{c o_{2}}}{1}$
$\frac{6.5}{2} = n_{c o_{2}}$
Mass of $C O_{2} = \frac{6.5}{2} \times 44 = 143 g m$