Question

Cinnamic acid is formed when $C_6{H}_5—CHO$ condenses with $(C{H}_{3}CO{)}_{2}O$ in presence of

• A. concentrated $H_{2}S{O}_4$
• B. sodium acetate
• C. sodium metal
• D. anhydrous $ZnC{l}_2$

Answer 1

Answer: (B)

When $C_6{H}_{5}CHO$ condenses with $(C{H}_{3}CO{)}_{2}O$ in presence of sodium acetate then cinnamic acid is formed. This reaction is called Perkin reaction
$\underset{\text{Benzaldehyde}}{C_6{H}_5—CHO}+\underset{\text{Acetic anhydnde}}{(C{H}_{3}CO{)}_{2}O}\underset{100^{\circ }C}{\overset{C{H}_{3}COONa}{\to }}$
$\underset{\text{Cinnamic acid}}{C_6{H}_{5}CH=CHCOOH}+\underset{\text{Acetic acid}}{C{H}_{3}COOH}$