Choose the correct statement(s) among the following:

Question

Choose the correct statement(s) among the following: (A) [ FeCl 4]-has tetrahedral geometry (B) [ Co ( en )( NH 3)2 Cl 2]+has 2 geometrical isomers (C) [ FeCl 4]-has higher spin-only magnetic moment than [ Co ( en )( NH 3)2 Cl 2]- (D) The cobalt ion in [ Co ( en )( NH 3)2 Cl 2]+has s p3 d2 hybridization

Tardigrade Admin · Accepted Answer

[ Co ( en )( NH 3)2 Cl 2]+ has 3 geometrical isomers, one of them is optically active. So, it has 4 stereoisomers.

I and II are enantiomers. Co +3=3 d6 d2 s p3 hybridization

Q. Choose the correct statement(s) among the following:

$[F e C l_{4}]^{-}$ has tetrahedral geometry

$[C o (e n) (N H_{3})_{2} C l_{2}]^{+}$ has 2 geometrical isomers

$[F e C l_{4}]^{-}$ has higher spin-only magnetic moment than $[C o (e n) (N H_{3})_{2} C l_{2}]^{-}$

The cobalt ion in $[C o (e n) (N H_{3})_{2} C l_{2}]^{+}$ has $s p^{3} d^{2}$ hybridization

$[C o (e n) (N H_{3})_{2} C l_{2}]^{+}$ has $3$ geometrical isomers, one of them is optically active. So, it has $4$ stereoisomers.

I and II are enantiomers. $C o^{+ 3} = 3 d^{6}$
$d^{2} s p^{3}$ hybridization

Q. Choose the correct statement(s) among the following:

[FeCl4​]−has tetrahedral geometry

[Co(en)(NH3​)2​Cl2​]+has 2 geometrical isomers

[FeCl4​]−has higher spin-only magnetic moment than [Co(en)(NH3​)2​Cl2​]−

The cobalt ion in [Co(en)(NH3​)2​Cl2​]+has sp3d2 hybridization

[Co(en)(NH3​)2​Cl2​]+ has 3 geometrical isomers, one of them is optically active. So, it has 4 stereoisomers. I and II are enantiomers. Co+3=3d6 d2sp3 hybridization

$[F e C l_{4}]^{-}$ has tetrahedral geometry

$[C o (e n) (N H_{3})_{2} C l_{2}]^{+}$ has 2 geometrical isomers

$[F e C l_{4}]^{-}$ has higher spin-only magnetic moment than $[C o (e n) (N H_{3})_{2} C l_{2}]^{-}$

The cobalt ion in $[C o (e n) (N H_{3})_{2} C l_{2}]^{+}$ has $s p^{3} d^{2}$ hybridization

$[C o (e n) (N H_{3})_{2} C l_{2}]^{+}$ has $3$ geometrical isomers, one of them is optically active. So, it has $4$ stereoisomers.

I and II are enantiomers. $C o^{+ 3} = 3 d^{6}$
$d^{2} s p^{3}$ hybridization