Chlorophyll present in green leaves of plants absorbs light at 4.620 × 1014 Hz. Which part of the electromagnetic spectrum does it belong to ?

Question

Chlorophyll present in green leaves of plants absorbs light at 4.620 × 1014 Hz. Which part of the electromagnetic spectrum does it belong to ? (A) UV (B) IR (C) Far lR (D) Visible

Tardigrade Admin · Accepted Answer

λ=( c / v )=(3.0 × 108 ms -1/4.620 × 1014 Hz ) =0.6494 × 10-6 m =649.4 nm Thus, it belongs to visible region

Q. Chlorophyll present in green leaves of plants absorbs light at $4.620 \times 1 0^{14} Hz$ . Which part of the electromagnetic spectrum does it belong to ?

UV

IR

Far lR

Visible

$λ = \frac{c}{v} = \frac{3.0 \times 1 0 ^{8} m s ^{- 1}}{4.620 \times 1 0 ^{14} Hz}$
$= 0.6494 \times 1 0^{- 6} m$
$= 649.4 nm$
Thus, it belongs to visible region

Q. Chlorophyll present in green leaves of plants absorbs light at 4.620×1014Hz. Which part of the electromagnetic spectrum does it belong to ?

UV

IR

Far lR

Visible

λ=vc​=4.620×1014Hz3.0×108ms−1​ =0.6494×10−6m =649.4nm Thus, it belongs to visible region

Q. Chlorophyll present in green leaves of plants absorbs light at $4.620 \times 1 0^{14} Hz$ . Which part of the electromagnetic spectrum does it belong to ?

$λ = \frac{c}{v} = \frac{3.0 \times 1 0 ^{8} m s ^{- 1}}{4.620 \times 1 0 ^{14} Hz}$
$= 0.6494 \times 1 0^{- 6} m$
$= 649.4 nm$
Thus, it belongs to visible region