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Q.
Chlorophyll present in green leaves of plants absorbs light at $4.620 \times 10^{14} Hz$. Which part of the electromagnetic spectrum does it belong to ?
ManipalManipal 2014
Solution:
$\lambda=\frac{ c }{ v }=\frac{3.0 \times 10^{8} ms ^{-1}}{4.620 \times 10^{14} Hz } $
$=0.6494 \times 10^{-6} m $
$=649.4 \,nm$
Thus, it belongs to visible region