Chloromethane on treatment with excess of ammonia yields mainly

Question

Chloromethane on treatment with excess of ammonia yields mainly (A)  (B) N-methylmethanamine (CH3—NH—CH3) (C) methanamine (CH3NH2) (D) mixture containing all these in equal proportion

Tardigrade Admin · Accepted Answer

underset textChloromethaneCH3Cl + underset text(excess)NH3arrow underset textMethanamineCH3NH2 + HCl Primary amine is obtained as a major product by taking large excess of ammonia.

Q. Chloromethane on treatment with excess of ammonia yields mainly

$N$ -methylmethanamine $(C H_{3} — N H — C H_{3})$

methanamine $(C H_{3} N H_{2})$

mixture containing all these in equal proportion

$Chloromethane C H_{3} Cl + (excess) N H_{3} \to Methanamine C H_{3} N H_{2} + H Cl$
Primary amine is obtained as a major product by taking large excess of ammonia.

Q. Chloromethane on treatment with excess of ammonia yields mainly

N-methylmethanamine (CH3​—NH—CH3​)

methanamine (CH3​NH2​)

mixture containing all these in equal proportion

ChloromethaneCH3​Cl​+(excess)NH3​​→MethanamineCH3​NH2​​+HCl Primary amine is obtained as a major product by taking large excess of ammonia.

$N$ -methylmethanamine $(C H_{3} — N H — C H_{3})$

methanamine $(C H_{3} N H_{2})$

$Chloromethane C H_{3} Cl + (excess) N H_{3} \to Methanamine C H_{3} N H_{2} + H Cl$
Primary amine is obtained as a major product by taking large excess of ammonia.