Charge q2 is at the centre of a circular path with radius r. Work done in carrying charge q1 once around this equipotential path, would be

Question

Charge q2 is at the centre of a circular path with radius r. Work done in carrying charge q1 once around this equipotential path, would be (A)  (1/ 4 π ε0) × ( q1 q2 / r2 ) (B)  (1/ 4 π ε0 ) × ( q1 q2 /r) (C) zero (D) infinite

Tardigrade Admin · Accepted Answer

Work done on carrying a charge from one place to another on an equipotential surface is zero.

Q. Charge $q_{2}$ is at the centre of a circular path with radius r. Work done in carrying charge $q_{1}$ once around this equipotential path, would be

$\frac{1}{4 π ε _{0}} \times \frac{q _{1} q _{2}}{r ^{2}}$

$\frac{1}{4 π ε _{0}} \times \frac{q _{1} q _{2}}{r}$

zero

infinite

Work done on carrying a charge from one place to another on an equipotential surface is zero.

Q. Charge q2​ is at the centre of a circular path with radius r. Work done in carrying charge q1​ once around this equipotential path, would be

4πε0​1​×r2q1​q2​​

4πε0​1​×rq1​q2​​

zero

infinite

Work done on carrying a charge from one place to another on an equipotential surface is zero.

Q. Charge $q_{2}$ is at the centre of a circular path with radius r. Work done in carrying charge $q_{1}$ once around this equipotential path, would be

$\frac{1}{4 π ε _{0}} \times \frac{q _{1} q _{2}}{r ^{2}}$

$\frac{1}{4 π ε _{0}} \times \frac{q _{1} q _{2}}{r}$