Charge on a body is q1 and it is used to charge another body by induction. Charge on second body is found to be q2 after charging. Then,

Question

Charge on a body is q1 and it is used to charge another body by induction. Charge on second body is found to be q2 after charging. Then, (A) (q1/q2)=1 (B) (q1/q2)<1 (C) (q1/q2) ≤ 1 (D) (q1/q2) ≥ 1

Tardigrade Admin · Accepted Answer

Correct answer is (d) (q1/q2) ≥ 1

Q. Charge on a body is $q_{1}$ and it is used to charge another body by induction. Charge on second body is found to be $q_{2}$ after charging. Then,

$\frac{q _{1}}{q _{2}} = 1$

$\frac{q _{1}}{q _{2}} < 1$

$\frac{q _{1}}{q _{2}} \leq 1$

$\frac{q _{1}}{q _{2}} \geq 1$

Correct answer is (d) $\frac{q _{1}}{q _{2}} \geq 1$

Q. Charge on a body is q1​ and it is used to charge another body by induction. Charge on second body is found to be q2​ after charging. Then,

q2​q1​​=1

q2​q1​​<1

q2​q1​​≤1

q2​q1​​≥1