CH3 -CH = CH2 -[500°C][Cl2]X. X is

Question

CH3 -CH = CH2 ->[500°C][Cl2]X. X is (A) ClCH2 -C H = CH2 (B)  (C) CH3 -CH = CHCl (D) none of the above

Tardigrade Admin · Accepted Answer

The alkyl group of the alkenes undergo substitution at high temperature. Chlorine or bromine replace hydrogen of the alpha carbon atom with respect to the double bond of alkyl group at about 500°C without breaking the double bond (allylic substitution)

Q. $CH X_{3} - CH = CH X_{2} 500 X^{\circ} C Cl X_{2} X . X$ is

$ClC H_{2} - C H = C H_{2}$

$C H_{3} - C H = C H Cl$

none of the above

The alkyl group of the alkenes undergo substitution at high temperature. Chlorine or bromine replace hydrogen of the alpha carbon atom with respect to the double bond of alkyl group at about $50 0^{\circ} C$ without breaking the double bond (allylic substitution)

Q. CHX3​ −CH=CHX2​500X∘CClX2​​X.X is

ClCH2​−CH=CH2​

CH3​−CH=CHCl

none of the above

The alkyl group of the alkenes undergo substitution at high temperature. Chlorine or bromine replace hydrogen of the alpha carbon atom with respect to the double bond of alkyl group at about 500∘C without breaking the double bond (allylic substitution)

Q. $CH X_{3} - CH = CH X_{2} 500 X^{\circ} C Cl X_{2} X . X$ is

$ClC H_{2} - C H = C H_{2}$

$C H_{3} - C H = C H Cl$

The alkyl group of the alkenes undergo substitution at high temperature. Chlorine or bromine replace hydrogen of the alpha carbon atom with respect to the double bond of alkyl group at about $50 0^{\circ} C$ without breaking the double bond (allylic substitution)