CH3 - CH = CH - CH = N - CH3 -[LiAlH4] What is final product

Question

CH3 - CH = CH - CH = N - CH3 ->[LiAlH4] What is final product (A) CH3 - CH2 - CH2 - CH2 - NH - CH3 (B) CH3 - CH = CH - CH2 - NH - CH3 (C) CH3 - CH2 - CH2 - CH - N - CH3 (D) CH3 - CH = CH - CH2 - OH

Tardigrade Admin · Accepted Answer

CH3 - CH = CH - CH = N - CH3 ->[LiAlH4] CH3 - CH = CH - CH2 - NH - CH3 LiAlH4 reduces imine into Amine but does not reduces C=C double bond

Q. $CH X_{3} - CH = CH - CH = N - CH X_{3} LiAlH X_{4}$
What is final product

$CH X_{3} - CH X_{2} - CH X_{2} - CH X_{2} - NH - CH X_{3}$

$CH X_{3} - CH = CH - CH X_{2} - NH - CH X_{3}$

$CH X_{3} - CH X_{2} - CH X_{2} - CH - N - CH X_{3}$

$CH X_{3} - CH = CH - CH X_{2} - OH$

$CH X_{3} - CH = CH - CH = N - CH X_{3} LiAlH X_{4} CH X_{3} - CH = CH - CH X_{2} - NH - CH X_{3}$
$LiAlH X_{4}$ reduces imine into Amine but does not reduces C=C double bond

Q. CHX3​−CH=CH−CH=N−CHX3​LiAlHX4​​ What is final product

CHX3​−CHX2​−CHX2​−CHX2​−NH−CHX3​

CHX3​−CH=CH−CHX2​−NH−CHX3​

CHX3​−CHX2​−CHX2​−CH−N−CHX3​

CHX3​−CH=CH−CHX2​−OH