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  4. CH3 - CH = CH - CH = N - CH3 ->[LiAlH4] What is final product

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Q. $\ce{CH3 - CH = CH - CH = N - CH3 ->[LiAlH_4]}$
What is final product

Solution:

$\ce{CH3 - CH = CH - CH = N - CH3 ->[LiAlH_4] CH3 - CH = CH - CH2 - NH - CH3}$
$\ce{LiAlH_4}$ reduces imine into Amine but does not reduces C=C double bond