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Tardigrade
Question
Chemistry
CH2 = CH2 ->[HBr] X ->[Aq. KOH] Y ->[Na2CO3][I2] Z In the above reaction sequence, Z is
Q.
CH
X
2
=
CH
X
2
HBr
X
Aq
⋅
KOH
Y
N
a
2
C
O
3
I
2
Z
In the above reaction sequence,
Z
is
2248
168
Punjab PMET
Punjab PMET 2009
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A
C
2
H
5
O
H
B
C
2
H
5
I
C
C
H
3
C
H
O
D
C
H
I
3
Solution:
C
H
2
=
C
H
2
+
H
B
r
⟶
X
C
H
3
−
C
H
2
B
r
X
C
H
3
C
H
2
B
r
Aq. KOH
-KBr
ethyl
alcohol
Y
CH
X
3
CH
X
2
OH
C
H
3
C
H
2
O
H
+
N
a
C
O
3
+
I
2
(iodoform
test)
iodoform
Z
CHI
X
3
+
H
COON
a
+
N
a
I
+
C
O
2
+
H
2
O