Question

$\ce{CH2 = CH2 ->[HBr] X} \ce{->[Aq. KOH] Y}\ce{ ->[{Na_2CO_3}][{I_2}] Z}$ In the above reaction sequence, $ Z $ is

• A. $C_{2}H_{5}OH$
• B. $C_{2}H_{5}I$
• C. $CH_{3}CHO$
• D. $CHI_{3}$

Answer 1

Answer: (D)

$CH_2 = CH_2 + HBr \longrightarrow \underset{X}{CH _{3}- CH _{2} Br}$
$\underset{X}{CH_3CH_2Br}\ce{ ->[{Aq. KOH}][{-KBr}] \underset{ethyl\,alcohol \, Y}{CH_3CH_2OH}}$
$CH_3CH_2OH + NaCO_3 +I_2\ce{ ->[{}][{(iodoform \,test)}] \underset{iodoform\,Z}{CHI3}} + HCOONa + NaI + CO_2 +H_2O$