CH3CH2Cl undergoes homolytic fission produces

Question

CH3CH2Cl undergoes homolytic fission produces (A) CH3 overset bulletCH2 and overset bulletCl (B) CH 3 dot C 2 and Cl ⊕ (C) CH 3 C ⊕ H 2 and Cl - (D) CH 3 C ⊕ H 2 and dot C l

Tardigrade Admin · Accepted Answer

Homolytic cleavage is the breaking of a covalent bond in such a way that each fragment gets one of the shared electrons.
The word homolytic comes from the Greek homoios, "equal", and lysis, "loosening".
For example, the homolytic cleavage of a

C - Cl

bond is
Homolytic cleavage produces free radicals - atoms with unpaired valence electrons.

H_{3} C H_{2} C^{-} Cl \to H_{3} C H_{2} C^{\oplus}

and

C l^{-}

Q. $C H_{3} C H_{2} Cl$ undergoes homolytic fission produces

$C H_{3} C ∙ H_{2}$ and $C ∙ l$

$C H_{3} \dot{C}_{2}$ and $C l^{\oplus}$

$C H_{3} C^{\oplus} H_{2}$ and $C l^{-}$

$C H_{3} C^{\oplus} H_{2}$ and $\dot{C}$ l

Q. CH3​CH2​Cl undergoes homolytic fission produces

CH3​C∙H2​ and C∙l

CH3​C˙2​ and Cl⊕

CH3​C⊕H2​ and Cl−

CH3​C⊕H2​ and C˙ l

Q. $C H_{3} C H_{2} Cl$ undergoes homolytic fission produces

$C H_{3} C ∙ H_{2}$ and $C ∙ l$

$C H_{3} \dot{C}_{2}$ and $C l^{\oplus}$

$C H_{3} C^{\oplus} H_{2}$ and $C l^{-}$

$C H_{3} C^{\oplus} H_{2}$ and $\dot{C}$ l