CH 3 COOH + H 2 O leftharpoons CH 3 COO -+ H 3 O + In the above process, conjugate base of strong acid is :

Question

CH 3 COOH + H 2 O leftharpoons CH 3 COO -+ H 3 O + In the above process, conjugate base of strong acid is : (A) H 2 O (B) CH 3 COO - (C) CH 3 COOH (D) H 3 O +

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/84b53b65b968a336ed83c23cd2130ff5-.png" /> Strong Acid ( H 3 O +)conjugate base will be H 2 O

Q. $C H_{3} COO H + H_{2} O ⇌ C H_{3} CO O^{-} + H_{3} O^{+}$ In the above process, conjugate base of strong acid is :

$H_{2} O$

$C H_{3} CO O^{-}$

$C H_{3} COO H$

$H_{3} O^{+}$

Strong Acid $(H_{3} O^{+})$ conjugate base will be $H_{2} O$

Q. CH3​COOH+H2​O⇌CH3​COO−+H3​O+ In the above process, conjugate base of strong acid is :

H2​O

CH3​COO−

CH3​COOH

H3​O+