1. Tardigrade
  2. Question
  3. Chemistry
  4. CH 3 COOH + H 2 O leftharpoons CH 3 COO -+ H 3 O + In the above process, conjugate base of strong acid is :

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. $CH _{3} COOH + H _{2} O \rightleftharpoons CH _{3} COO ^{-}+ H _{3} O ^{+}$ In the above process, conjugate base of strong acid is :

Equilibrium

Solution:

image
Strong Acid $\left( H _{3} O ^{+}\right)$conjugate base will be $H _{2} O$