CH 3 COOH + C 2 H 5 OH leftharpoons CH 3 COOC 2 H 5+ H 2 O In the above reaction; one mole each of acetic acid and alcohol are heated in the presence of little conc. H 2 SO 4 On equilibrium being attained

Question

CH 3 COOH + C 2 H 5 OH leftharpoons CH 3 COOC 2 H 5+ H 2 O In the above reaction; one mole each of acetic acid and alcohol are heated in the presence of little conc. H 2 SO 4 On equilibrium being attained (A) 1 mole of ethyl acetate is formed (B) 2 moles of ethyl acetate are formed (C) 1 / 3 mole of ethyl acetate is formed (D) unpredictable

Tardigrade Admin · Accepted Answer

Concentration cannot be calculated without the value of equilibrium constant

Q. $C H_{3} COO H + C_{2} H_{5} O H ⇌ C H_{3} COO C_{2} H_{5} + H_{2} O$
In the above reaction; one mole each of acetic acid and alcohol are heated in the presence of little conc. $H_{2} S O_{4}$ On equilibrium being attained

1 mole of ethyl acetate is formed

2 moles of ethyl acetate are formed

$1/3$ mole of ethyl acetate is formed

unpredictable

Concentration cannot be calculated without the value of equilibrium constant

Q. CH3​COOH+C2​H5​OH⇌CH3​COOC2​H5​+H2​O In the above reaction; one mole each of acetic acid and alcohol are heated in the presence of little conc. H2​SO4​ On equilibrium being attained

1 mole of ethyl acetate is formed

2 moles of ethyl acetate are formed

1/3 mole of ethyl acetate is formed

unpredictable

Concentration cannot be calculated without the value of equilibrium constant

Q. $C H_{3} COO H + C_{2} H_{5} O H ⇌ C H_{3} COO C_{2} H_{5} + H_{2} O$
In the above reaction; one mole each of acetic acid and alcohol are heated in the presence of little conc. $H_{2} S O_{4}$ On equilibrium being attained

$1/3$ mole of ethyl acetate is formed