Tardigrade
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Tardigrade
Question
Chemistry
CH 3 CHO + NH 2 OH → CH 3 CH = N - OH The above reaction is carried out at
Q.
C
H
3
C
H
O
+
N
H
2
O
H
→
C
H
3
C
H
=
N
−
O
H
The above reaction is carried out at
2145
248
Aldehydes Ketones and Carboxylic Acids
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A
pH =1
B
pH =4.5
C
pH =12
D
pH =14
Solution:
More Basic condititions:
O
H
−
may attack
C
H
3
C
H
O
More Acidic conditions :
H
+
may attack
N
H
2
−
O
H
At optimum pH i.e 4.5 reaction takes place