CH3 - CH = CH2 -[Br2/hv][ text(low conc.)] (A) ; Product (A) of the reaction is :

Question

CH3 - CH = CH2 ->[Br2/hv][ text(low conc.)] (A) ; Product (A) of the reaction is : (A) CH3 - underset overset|BrCH - CH2 - Br (B) H2C = CH - CH2 - Br (C) CH3 - underset overset|BrC - CH2 (D) Br - CH2 - CH2-CH2-Br

Tardigrade Admin · Accepted Answer

CH3 - CH = CH2 ->[Br2/hv][ underset(FRSR) text(low conc.)] underset overset|BrCH2 - CH = CH2

Q. $C H_{3} - C H = C H_{2} Br X_{2} / hv (low conc.) (A)$ ;
Product $(A)$ of the reaction is :

$C H_{3} - B ∣ r C H - C H_{2} - B r$

$H_{2} C = C H - C H_{2} - B r$

$C H_{3} - B ∣ r C - C H_{2}$

$B r - C H_{2} - C H_{2} - C H_{2} - B r$

$C H_{3} - C H = C H_{2} Br X_{2} / hv (FRSR) (low conc.) B ∣ r C H_{2} - C H = C H_{2}$

Q. CH3​−CH=CH2​BrX2​/hv(low conc.)​(A); Product (A) of the reaction is :

CH3​−B∣rC​H−CH2​−Br

H2​C=CH−CH2​−Br

CH3​−B∣rC​−CH2​

Br−CH2​−CH2​−CH2​−Br