Q. $C H_{3} - C H_{2} - C H_{2} - C ∣∣ O - ON a Kolbe’s (aq. electrolysis X$
$Cr X_{2} O X_{3}, Al X_{2} O X_{3} Δ & pr Y$

1468 196 Report Error

A

$C H_{3} - C H_{2} - C H_{2} - C ∣ H_{3} C H - ON a$

14%

B

Option 2 Image

29%

C

Option 3 Image

43%

D

$C H_{3} - C H = C H - C H_{2} - C H_{2} - C H_{3}$

14%

Solution:

Correct answer is (c)

Solution Image