(CH3)4N+ OH- is stronger base than (CH3)3N+ HOH- due to

Question

(CH3)4N+ OH- is stronger base than (CH3)3N+ HOH- due to (A) intramolecular hydrogen bonding in (CH3)3N+ HOH- (B) intermolecular hydrogen bonding in (CH3)4N+ OH- (C) intermolecular hydrogen bonding of (CH3)3N+ HOH- with water (D) none of these.

Tardigrade Admin · Accepted Answer

Intramolecular hydrogen bonding is possible in (CH3)3N+HOH- which decreases the basic strength of compound.

Q. $(C H_{3})_{4} N^{+} O H^{-}$ is stronger base than $(C H_{3})_{3} N^{+} H O H^{-}$ due to

intramolecular hydrogen bonding in $(C H_{3})_{3} N^{+} H O H^{-}$

intermolecular hydrogen bonding in $(C H_{3})_{4} N^{+} O H^{-}$

intermolecular hydrogen bonding of $(C H_{3})_{3} N^{+} H O H^{-}$ with water

none of these.

Intramolecular hydrogen bonding is possible in $(C H_{3})_{3} N^{+} H O H^{-}$ which decreases the basic strength of compound.

Q. (CH3​)4​N+OH− is stronger base than (CH3​)3​N+HOH− due to

intramolecular hydrogen bonding in (CH3​)3​N+HOH−

intermolecular hydrogen bonding in (CH3​)4​N+OH−

intermolecular hydrogen bonding of (CH3​)3​N+HOH− with water