Carnot cycle (reversible) of a gas represented by a Pressure-Volume curve is shown in the diagram Consider the following statements I. Area A B C D= Work done on the gas II. Area A B C D= Net heat absorbed III. Change in the internal energy in cycle =0 Which of these are correct?

Question

Carnot cycle (reversible) of a gas represented by a Pressure-Volume curve is shown in the diagram Consider the following statements I. Area A B C D= Work done on the gas II. Area A B C D= Net heat absorbed III. Change in the internal energy in cycle =0 Which of these are correct? (A) I only (B) II only (C) II and III (D) I, II and III

Tardigrade Admin · Accepted Answer

Work done by the gas (as cyclic process is clockwise)

∴ Δ W =

Area

A BC D

So from the first law of thermodynamics

Δ Q

(net heat absorbed)

= Δ W =

Area

A BC D

As change in internal energy in cycle

Δ U = 0

.

Q. Carnot cycle (reversible) of a gas represented by a Pressure-Volume curve is shown in the diagram Consider the following statements I. Area ABCD= Work done on the gas II. Area ABCD= Net heat absorbed III. Change in the internal energy in cycle =0 Which of these are correct?

I only

II only

II and III

I, II and III

Work done by the gas (as cyclic process is clockwise) ∴ΔW= Area ABCD So from the first law of thermodynamics ΔQ (net heat absorbed) =ΔW= Area ABCD As change in internal energy in cycle ΔU=0.

Q. Carnot cycle (reversible) of a gas represented by a Pressure-Volume curve is shown in the diagram Consider the following statements
I. Area $A BC D =$ Work done on the gas
II. Area $A BC D =$ Net heat absorbed
III. Change in the internal energy in cycle $= 0$
Which of these are correct?

Work done by the gas (as cyclic process is clockwise)
$∴ Δ W =$ Area $A BC D$
So from the first law of thermodynamics $Δ Q$
(net heat absorbed) $= Δ W =$ Area $A BC D$
As change in internal energy in cycle $Δ U = 0$ .