Carbon cannot be used in the reduction of Al2O3 because:

Question

Carbon cannot be used in the reduction of Al2O3 because: (A) it is non-metal (B) the heat of formation of CO2 is more than that of Al2O3 (C) pure carbon is not easily available (D) the heat of formation of Al2O3 is too high

Tardigrade Admin · Accepted Answer

In Ellingham diagram, the Δf Go of Al2O3 lies below that of CO2. If reduction is carried out at very high temperature, the Al produced will react with carbon forming Al4C3.

Q. Carbon cannot be used in the reduction of $A l_{2} O_{3}$ because:

it is non-metal

the heat of formation of $C O_{2}$ is more than that of $A l_{2} O_{3}$

pure carbon is not easily available

the heat of formation of $A l_{2} O_{3}$ is too high

In Ellingham diagram, the $Δ_{f} G^{o}$ of $A l_{2} O_{3}$ lies below that of $C O_{2}$ . If reduction is carried out at very high temperature, the $A l$ produced will react with carbon forming $A l_{4} C_{3}$ .

Q. Carbon cannot be used in the reduction of Al2​O3​ because:

it is non-metal

the heat of formation of CO2​ is more than that of Al2​O3​

pure carbon is not easily available

the heat of formation of Al2​O3​ is too high

In Ellingham diagram, the Δf​Go of Al2​O3​ lies below that of CO2​. If reduction is carried out at very high temperature, the Al produced will react with carbon forming Al4​C3​.

Q. Carbon cannot be used in the reduction of $A l_{2} O_{3}$ because:

the heat of formation of $C O_{2}$ is more than that of $A l_{2} O_{3}$

the heat of formation of $A l_{2} O_{3}$ is too high

In Ellingham diagram, the $Δ_{f} G^{o}$ of $A l_{2} O_{3}$ lies below that of $C O_{2}$ . If reduction is carried out at very high temperature, the $A l$ produced will react with carbon forming $A l_{4} C_{3}$ .