Calculate the velocity of an electron placed in the second orbit of Li2+ ion.

Question

Calculate the velocity of an electron placed in the second orbit of Li2+ ion. (A) 0.521 m s-1 (B) 3.27 × 103 m s-1 (C) 4.23 × 103 m s-1 (D) 3.27 × 106 m s-1

Tardigrade Admin · Accepted Answer

The velocity of an electron in nth shell of the hydrogen like atom = (2.18×106 ms-1× Z/n) On putting Z = 3 and n = 2, v=(2.18×106×3/2)=3.27×106 m s-1

Q. Calculate the velocity of an electron placed in the second orbit of $L i^{2 +}$ ion.

0.521 m s^-1

3.27 × 10³ m s^-1

4.23 × 10³ m s^-1

3.27 × 10⁶ m s^-1

The velocity of an electron in n^th shell of the hydrogen like atom = $\frac{2.18 \times 1 0 ^{6} m s ^{- 1} \times Z}{n}$
On putting Z = 3 and n = 2,
$v = \frac{2.18 \times 1 0 ^{6} \times 3}{2} = 3.27 \times 1 0^{6} m s^{- 1}$

Q. Calculate the velocity of an electron placed in the second orbit of Li2+ ion.

0.521 m s-1

3.27 × 103 m s-1

4.23 × 103 m s-1

3.27 × 106 m s-1