Vapour pressure of pure. water (solvent) at 100∘C , p∘=760mm.
Vapour pressure of solution, p= ?
Wt. of solvent, W=33g
Wt. of solute, w=3g
Mol. wt. of water (H2O),M=18
Mol. wt. of sugar (C12H22O11) m=12×12+22×1+11×16=342
According to Raoult's law, p∘p∘−p=WmwM ∴p=p∘−m×Ww×M×p∘ p=760−342×333×18×760 (∴p∘ for H2O=760mm) =760−3.19=756.90mm