Question

Calculate the value of magnetic moment for ${}_{26}F{e}^{3+}$ .

• A. $1.73BM$
• B. $3.87BM$
• C. $4.90BM$
• D. $5.92BM$

Answer 1

Answer: (D)

$\text{Fe }:3{\text{d}}^{6}4{\text{s}}^2$
$F{e}^{3+}:3d^{5}4s^o$
$\boxed{\uparrow }\boxed{\uparrow }\boxed{\uparrow }\boxed{\uparrow }\boxed{\uparrow }$
$n=5$
The formula of magnetic moment $\left(\text{µ}\right)$ :
$\sqrt{n\left(n+2\right)}BM$
Whereas:- $\text{n}=$ Number of unpaired electron
$\text{BM}=$ Bohr Magneton
$\text{µ}=\sqrt{35}\text{BM}$
$=5.92\text{BM}$