Question

Calculate the value of magnetic moment for $ \, _{26}F e^{3 +}$ .

• A. $1.73 \, BM$
• B. $3.87 \, BM$
• C. $4.90 \, BM$
• D. $5.92 \, BM$

Answer 1

Answer: (D)

$\text{Fe }:3\text{d}^{6}4\text{s}^{2}$
$Fe^{3 +}:3d^{5}4s^{o}$
$\boxed{\uparrow}\boxed{\uparrow}\boxed{\uparrow}\boxed{\uparrow}\boxed{\uparrow}$
$n=5$
The formula of magnetic moment $\left(\text{µ}\right)$ :
$\sqrt{n \, \left(n + 2\right)} \, BM$
Whereas:- $\text{n} \, =$ Number of unpaired electron
$\text{BM}=$ Bohr Magneton
$\text{µ} = \sqrt{35} \, \text{BM}$
$=5.92 \, \text{BM}$