Question

Calculate the surface area of a catalyst (in terms of $10^3$ cm${}^2$) that adsorbs $10^3$ cm${}^3$ of nitrogen reduced to $STP$ per gram in order to form the monolayer. The effective area occupied by $N_2$ molecule on the surface is $1.62\times 10^{-15}$ cm${}^2$

Answer 1

Answer: 4

No. of $N_2$ molecules$=\frac{10^3\times 6.023\times 10^{23}}{22400}=2.69\times 10^{22}$
Total area covered by $N_2=2.69\times 10^{22}\times 1.62\times 10^{-15}$
$=435\times 10^5$ cm${}^2$
$=4.35\times 10^3$ cm${}^2$