Calculate the steadystate current in the 2 Ω resistor shown in the circuit in the figure. The internal resistance of the battery is negligible and the capacitance of the condenser C is 0.2 μ F.

Question

Calculate the steadystate current in the 2 Ω resistor shown in the circuit in the figure. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/b50563d89d1d4f7dda4dfdd9a027888d-.jpeg" /> The internal resistance of the battery is negligible and the capacitance of the condenser C is 0.2 μ F. (A) 0.6 A (B) 0.9 A (C) 1.2 A (D) 0.1 A

Tardigrade Admin · Accepted Answer

At steady state, no current flows through the capacitor branch of the circuit.

2 Ω

and

3 Ω

are in parallel. Let their combined resistance be

R

.

∴ R = \frac{2 \times 3}{2 + 3} = \frac{2 \times 3}{5}

= 1.2 Ω

Net current supplied

= \frac{6}{1.2 + 2.8}

I = 1.5 A

I

divides into

I_{1}

and

I_{2}

2 I_{1} = 3 I_{2}

[Potential Difference is same]
or

I_{2} = 2 I_{1} /3

I_{1} + I_{2} = 1.5

or

I_{1} + \frac{2 I _{1}}{3}

= 1.5

or

\frac{5 I _{1}}{3} = 1.5

or

I_{1} = \frac{1.5 \times 3}{5} A

= 0.9 A

Q. Calculate the steadystate current in the $2 Ω$ resistor shown in the circuit in the figure.

The internal resistance of the battery is negligible and the capacitance of the condenser $C$ is $0.2 μ F$ .

$0.6 A$

$0.9 A$

$1.2 A$

$0.1 A$

Q. Calculate the steadystate current in the 2Ω resistor shown in the circuit in the figure. The internal resistance of the battery is negligible and the capacitance of the condenser C is 0.2μF.

0.6A

0.9A

1.2A

0.1A

Q. Calculate the steadystate current in the $2 Ω$ resistor shown in the circuit in the figure.

The internal resistance of the battery is negligible and the capacitance of the condenser $C$ is $0.2 μ F$ .

$0.6 A$

$0.9 A$

$1.2 A$

$0.1 A$