Calculate the pH of buffer solution prepared by dissolving 0.20 mol of sodium cyanate (NaCNO) and 1.0 mol of cynic acid (HCNO) in enough water to make 1.0 litre of slution. Ka(.HCNO.)=2.0× 10- 4.

Question

Calculate the pH of buffer solution prepared by dissolving 0.20 mol of sodium cyanate (NaCNO) and 1.0 mol of cynic acid (HCNO) in enough water to make 1.0 litre of slution. Ka(.HCNO.)=2.0× 10- 4. (A) 0 (B) 3.0 (C) 4.4 (D) 5.0

Tardigrade Admin · Accepted Answer

pH =-logKa(.HCNO.)+log([. N a C N O ]./[. H C N O ].) =- log (2.0 × 10-4)+ log (0.20 mathrm~mol / mathrmL/1.0 mathrm~mol / mathrmL) =3.7+(.-0.67.) =3.03∼ eq3.0

Q. Calculate the pH of buffer solution prepared by dissolving 0.20 mol of sodium cyanate (NaCNO) and 1.0 mol of cynic acid (HCNO) in enough water to make 1.0 litre of slution. $K_{a} (H CNO) = 2.0 \times 1 0^{- 4} .$

0

3.0

4.4

5.0

pH $= - l o g K_{a} (H CNO) + l o g \frac{[ N a CNO ]}{[ H CNO ]}$

$= - lo g (2.0 \times 1 0^{- 4}) + lo g \frac{0.20 mol / L}{1.0 mol / L}$

$= 3.7 + (- 0.67)$

$= 3.03 \sim e q 3.0$

Q. Calculate the pH of buffer solution prepared by dissolving 0.20 mol of sodium cyanate (NaCNO) and 1.0 mol of cynic acid (HCNO) in enough water to make 1.0 litre of slution. Ka​(HCNO)=2.0×10−4.

0

3.0

4.4

5.0

pH =−logKa​(HCNO)+log[HCNO][NaCNO]​ =−log(2.0×10−4)+log1.0 mol/L0.20 mol/L​ =3.7+(−0.67) =3.03∼eq3.0

Q. Calculate the pH of buffer solution prepared by dissolving 0.20 mol of sodium cyanate (NaCNO) and 1.0 mol of cynic acid (HCNO) in enough water to make 1.0 litre of slution. $K_{a} (H CNO) = 2.0 \times 1 0^{- 4} .$

pH $= - l o g K_{a} (H CNO) + l o g \frac{[ N a CNO ]}{[ H CNO ]}$

$= - lo g (2.0 \times 1 0^{- 4}) + lo g \frac{0.20 mol / L}{1.0 mol / L}$

$= 3.7 + (- 0.67)$

$= 3.03 \sim e q 3.0$