Calculate the number of hours of service that can be derived at 1 atm and 300 K from an acetylene lamp containing 640 g calcium carbide. Given that the lamp requires 50 L acetylene gas at 1 atm and 300 K for one hour. [Take 0.0821 × 300=25 ]

Question

Calculate the number of hours of service that can be derived at 1 atm and 300 K from an acetylene lamp containing 640 g calcium carbide. Given that the lamp requires 50 L acetylene gas at 1 atm and 300 K for one hour. [Take 0.0821 × 300=25 ] (A) 5 hr (B) 6 hr (C) 5.5 hr (D) 6.5 hr

Tardigrade Admin · Accepted Answer

CaC 2+2 H 2 O arrow Ca ( OH )2+ C 2 H 2 640 / 64=10 mol V=(n R T/P)=(10 × 0.0821 × 300/1)=250 L ∴ T=(250 L /50 L / hr )=5 hr

Q. Calculate the number of hours of service that can be derived at 1 atm and $300 K$ from an acetylene lamp containing $640 g$ calcium carbide. Given that the lamp requires $50 L$ acetylene gas at $1 a t m$ and $300 K$ for one hour. [Take $0.0821 \times 300 = 25$ ]

5 hr

6 hr

5.5 hr

6.5 hr

$C a C_{2} + 2 H_{2} O \to C a (O H)_{2} + C_{2} H_{2}$

$640/64 = 10 m o l$

$V = \frac{n RT}{P} = \frac{10 \times 0.0821 \times 300}{1} = 250 L$

$∴ T = \frac{250 L}{50 L / h r} = 5 h r$

Q. Calculate the number of hours of service that can be derived at 1 atm and 300K from an acetylene lamp containing 640g calcium carbide. Given that the lamp requires 50L acetylene gas at 1atm and 300K for one hour. [Take 0.0821×300=25 ]