Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Calculate the number of hours of service that can be derived at 1 atm and $300 \,K$ from an acetylene lamp containing $640 \,g$ calcium carbide. Given that the lamp requires $50\, L$ acetylene gas at $1 \,atm$ and $300\, K$ for one hour. [Take $0.0821 \times 300=25$ ]

States of Matter

Solution:

$CaC _{2}+2 H _{2} O \rightarrow Ca ( OH )_{2}+ C _{2} H _{2}$

$640 / 64=10 \,mol$

$V=\frac{n R T}{P}=\frac{10 \times 0.0821 \times 300}{1}=250 \,L $

$\therefore T=\frac{250 \,L }{50\, L / hr }=5\, hr$