Calculate the number of electrons lost during electrolysis of 2 g Cl - ions?

Question

Calculate the number of electrons lost during electrolysis of 2 g Cl - ions? (A) 4.69 × 1024 electrons (B) 3.39 × 1022 electrons (C) 7.39 × 1022 electrons (D) 3.59 × 1023 electrons

Tardigrade Admin · Accepted Answer

underset35.5 gCl- longrightarrow 1/2 Cl2 + underset 1 F(6.023 ×1023 textelectrons) e- 35.5 g text loses =6.023 × 1023 text electrons 2 g text will lose =(6.023 × 1023/35.5) × 2=3.39 × 1022

Q. Calculate the number of electrons lost during electrolysis of $2 g C l^{-}$ ions?

$4.69 \times 1 0^{24}$ electrons

$3.39 \times 1 0^{22}$ electrons

$7.39 \times 1 0^{22}$ electrons

$3.59 \times 1 0^{23}$ electrons

$35.5 g C l^{-} ⟶ 1/2 C l_{2} + 1 F (6.023 \times 1 0^{2} 3 electrons) e^{-}$
$35.5 g loses = 6.023 \times 1 0^{23} electrons$
$2 g will lose = \frac{6.023 \times 1 0 ^{23}}{35.5} \times 2 = 3.39 \times 1 0^{22}$

Q. Calculate the number of electrons lost during electrolysis of 2gCl− ions?

4.69×1024 electrons

3.39×1022 electrons

7.39×1022 electrons

3.59×1023 electrons