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Q. Calculate the number of electrons lost during electrolysis of $2\, g\, Cl ^{-}$ ions?

Electrochemistry

Solution:

$ \underset{35.5\,g}{Cl^-} \longrightarrow 1/2 Cl_2 + \underset {1 F(6.023 \times10^23 \text{electrons}) }{e^-}$
$35.5 \,g \text { loses } =6.023 \times 10^{23} \text { electrons } $
$2 \,g \text { will lose } =\frac{6.023 \times 10^{23}}{35.5} \times 2=3.39 \times 10^{22}$