Calculate the molality of a solution that contains 51.2 g of naphthalene. (C10H8), in 500 mL of carbon tetrachloride. The density of CCI4 is 1.60 g/mL

Question

Calculate the molality of a solution that contains 51.2 g of naphthalene. (C10H8), in 500 mL of carbon tetrachloride. The density of CCI4 is 1.60 g/mL (A) 0.250, m (B) 0.500 m (C) 0.750 m (D) 0.840 m

Tardigrade Admin · Accepted Answer

Given, WB= mass of naphthalene =51.2 g MB= molar mass of naphthalene ( C 10 H 8) =12 × 10+8=128 g WA= density (d) × volume (V)(∵ d=(w/V)) WA =1.60 gmL -1 × 500 ML =800 g ∵ m =(WB/MB) ×((1000/WA( kg ))) m =(51.2 × 1000/128 × 800)=0.5 m

Q. Calculate the molality of a solution that contains $51.2 g$ of naphthalene. $(C_{10} H_{8})$ , in $500 m L$ of carbon tetrachloride. The density of $CC I_{4}$ is $1.60 g / m L$

0.250, $m$

0.500 $m$

0.750 $m$

0.840 $m$

1.69 $m$

Q. Calculate the molality of a solution that contains 51.2g of naphthalene. (C10​H8​), in 500mL of carbon tetrachloride. The density of CCI4​ is 1.60g/mL

0.250, m

0.500 m

0.750 m

0.840 m

1.69 m