Calculate the mean kinetic energy of one gram of carbon dioxide gas. Carbon dioxide ((CO)2) is a triatomic gas (.O=C=O.) . (Given, N = Avogadro number, k = Boltzmann constant and molecular weight of CO2=44 )

Question

Calculate the mean kinetic energy of one gram of carbon dioxide gas. Carbon dioxide ((CO)2) is a triatomic gas (.O=C=O.) . (Given, N = Avogadro number, k = Boltzmann constant and molecular weight of CO2=44 ) (A) (3/88)NkT (B) (5/88)NkT (C) (6/88)NkT (D) (7/88)NkT

Tardigrade Admin · Accepted Answer

Mean KE of gas is, E=f× (μ R T/2) Degree of freedom for CO2 is f=7 E=7× ((m/M))× (R T/2)=((1/44))× (7 N k T/2)E=(7 N k T/88)

Q. Calculate the mean kinetic energy of one gram of carbon dioxide gas. Carbon dioxide $((CO)_{2})$ is a triatomic gas $(O = C = O)$ . (Given, $N$ = Avogadro number, $k$ = Boltzmann constant and molecular weight of $C O_{2} = 44$ )

$\frac{3}{88} N k T$

$\frac{5}{88} N k T$

$\frac{6}{88} N k T$

$\frac{7}{88} N k T$

Mean KE of gas is,
$E = f \times \frac{μ RT}{2}$
Degree of freedom for $C O_{2}$ is $f = 7$
$E = 7 \times (\frac{m}{M}) \times \frac{RT}{2} = (\frac{1}{44}) \times \frac{7 N k T}{2} E = \frac{7 N k T}{88}$

Q. Calculate the mean kinetic energy of one gram of carbon dioxide gas. Carbon dioxide ((CO)2​) is a triatomic gas (O=C=O) . (Given, N = Avogadro number, k = Boltzmann constant and molecular weight of CO2​=44 )

883​NkT

885​NkT

886​NkT

887​NkT