Question

Calculate the maximum emf induced when a square frame is making $240r.p.m$ each side of square being $20cm$ and magnetic field intensity is $500$ gauss?

• A. $5.01\times 10^{-2}V$
• B. $5.02\times 10^{-2}V$
• C. $5.03\times 10^{-2}V$
• D. $8\times 10^{-3}V$

Answer 1

Answer: (B)

As we know
$e=NAB\omega$
$e=1\times {\left(20\times 10^{-2}\right)}^2\times 500\times 10^{-4}\times 2\pi \times \frac{240}{60}$
$e=400\times 10^{-4}\times 500\times 10^{-4}\times 2\pi \times 4$
$e=20\times 4\times 10^{-4}\times 2\pi$
$=80\times 10^{-4}\times 2\pi$
$e=5.02\times 10^{-2}V$