Calculate the mass of BaCO3 produced when excess CO2 is bubbled through a solution containing 0.205 moles of Ba(O H)2 .

Question

Calculate the mass of BaCO3 produced when excess CO2 is bubbled through a solution containing 0.205 moles of Ba(O H)2 . (A) 40.5g (B) 48.5g (C) 4.5g (D) 60.5g

Tardigrade Admin · Accepted Answer

Ba(O H)2+CO2 arrow BaCO3+H2O Mole of Ba(O H)2:Mole of CO2::Mole of BaCO3:Mole of H2O Mole of BaCO3 formed=0.205 Weight of BaCO3 formed=0.205× 197.4=40.5g

Q. Calculate the mass of $B a C O_{3}$ produced when excess $C O_{2}$ is bubbled through a solution containing $0.205 m o l es o f B a (O H)_{2}$ .

$40.5 g$

$48.5 g$

$4.5 g$

$60.5 g$

$B a (O H)_{2} + C O_{2} \to B a C O_{3} + H_{2} O$

$M o l e o f B a (O H)_{2} : M o l e o f C O_{2} :: M o l e o f B a C O_{3} : M o l e o f H_{2} O$

$M o l e o f B a C O_{3} f or m e d = 0.205$

$W e i g h t o f B a C O_{3} f or m e d = 0.205 \times 197.4 = 40.5 g$

Q. Calculate the mass of BaCO3​ produced when excess CO2​ is bubbled through a solution containing 0.205molesofBa(OH)2​ .

40.5g

48.5g

4.5g

60.5g