Calculate the magnetic force per unit length that will act on a wire which makes an angle of 45° with the direction of a uniform magnetic field of 0.20 T and carries 10A of current.

Question

Calculate the magnetic force per unit length that will act on a wire which makes an angle of 45° with the direction of a uniform magnetic field of 0.20 T and carries 10A of current. (A) 2√2 N m- 1 (B) (2/√ 2) N m- 1 (C) (√ 2/2) N m- 1 (D) 4√2 N m- 1

Tardigrade Admin · Accepted Answer

I=10 A,θ =45o, B=0.2 T ∴ F=IlBsin θ ∴ (F/l)=IBsin 45o =10× 0.2× (1/√2)=(2/√2)N m- 1

Q. Calculate the magnetic force per unit length that will act on a wire which makes an angle of $4 5^{\circ}$ with the direction of a uniform magnetic field of $0.20 T$ and carries $10 A$ of current.

$22 N m^{- 1}$

$\frac{2}{2} N m^{- 1}$

$\frac{2}{2} N m^{- 1}$

$42 N m^{- 1}$

$I = 10 A, θ = 4 5^{o}, B = 0.2 T$
$∴ F = I lB s in θ$
$∴ \frac{F}{l} = I B s in 4 5^{o} = 10 \times 0.2 \times \frac{1}{2} = \frac{2}{2} N m^{- 1}$

Q. Calculate the magnetic force per unit length that will act on a wire which makes an angle of 45∘ with the direction of a uniform magnetic field of 0.20T and carries 10A of current.

22​Nm−1

​22​Nm−1

2​2​Nm−1

42​Nm−1

I=10A,θ=45o,B=0.2T ∴F=IlBsinθ ∴lF​=IBsin45o=10×0.2×2​1​=2​2​Nm−1

Q. Calculate the magnetic force per unit length that will act on a wire which makes an angle of $4 5^{\circ}$ with the direction of a uniform magnetic field of $0.20 T$ and carries $10 A$ of current.

$22 N m^{- 1}$

$\frac{2}{2} N m^{- 1}$

$\frac{2}{2} N m^{- 1}$

$42 N m^{- 1}$

$I = 10 A, θ = 4 5^{o}, B = 0.2 T$
$∴ F = I lB s in θ$
$∴ \frac{F}{l} = I B s in 4 5^{o} = 10 \times 0.2 \times \frac{1}{2} = \frac{2}{2} N m^{- 1}$