Calculate the ionic radius of a Cs+ ion, assuming that the cell edge length for CsCl is 0.4123 nm and that the ionic radius of a Cl− ion is 0.181 nm.

Question

Calculate the ionic radius of a Cs+ ion, assuming that the cell edge length for CsCl is 0.4123 nm and that the ionic radius of a Cl− ion is 0.181 nm. (A) 0.176 nm (B) 0.231 nm (C) 0.357 nm (D) 0.116 nm

Tardigrade Admin · Accepted Answer

r Cs ++r Cl - =(d text body /2)=(0.7141/2)=0.3571 nm r Cs + =0.3571-0.181=0.176 nm

Q. Calculate the ionic radius of a $C s^{+}$ ion, assuming that the cell edge length for $C s Cl$ is $0.4123 nm$ and that the ionic radius of a $C l^{-}$ ion is $0.181 nm$ .

$0.176 nm$

$0.231 nm$

$0.357 nm$

$0.116 nm$

$r_{C s^{+}} + r_{C l^{-}} = \frac{d _{body}}{2} = \frac{0.7141}{2} = 0.3571 nm$

$r_{C s^{+}} = 0.3571 - 0.181 = 0.176 nm$

Q. Calculate the ionic radius of a Cs+ ion, assuming that the cell edge length for CsCl is 0.4123nm and that the ionic radius of a Cl− ion is 0.181nm.

0.176nm

0.231nm

0.357nm

0.116nm